The frequency of the photon emitted when an electron jumps from n = 3 to n = 2 is given by f = ΔE / h. What is f?
Q1. The frequency of the photon emitted when an electron jumps from n = 3 to n = 2 is given by f = ΔE / h. What is f?
Answer: 4.57 * 10^14 Hz
Explanation: ΔE = 1.89 eV = 1.89 * 1.602 * 10^-19 J. f = ΔE / h = (1.89 * 1.602 * 10^-19) / (6.626 * 10^-34) = 4.57 * 10^14 Hz.