The wavelength of the photon emitted when an electron jumps from n = 4 to n = 2 is given by 1 / λ = R * (1 / 2² - 1 / 4²). What is λ?
Q1. The wavelength of the photon emitted when an electron jumps from n = 4 to n = 2 is given by 1 / λ = R * (1 / 2² - 1 / 4²). What is λ?
Answer: 486.1 nm
Explanation: 1 / λ = R * (1/4 - 1/16) = R * 3/16. λ = 16 / (3*R) = 486.1 nm, using R = 1.097 * 10^7 m^-1.