The ratio of the energies of the first and second excited states of hydrogen atom is
Q1. The ratio of the energies of the first and second excited states of hydrogen atom is
Answer: 4 / 9
Explanation: E2 = -13.6 / 2² = -3.4 eV, E3 = -1.51 eV. Ratio = E3 / E2 = (-1.51) / (-3.4) = 4/9.