A particle is executing SHM with maximum velocity 10 cm/s and maximum acceleration 40 cm/s². Its amplitude is
Q1. A particle is executing SHM with maximum velocity 10 cm/s and maximum acceleration 40 cm/s². Its amplitude is
Answer: 2.5 cm
Explanation: In SHM, v_max = Aω and a_max = Aω². Given v_max = 10 and a_max = 40. Dividing, ω = 4. So, A = v_max / ω = 10 / 4 = 2.5 cm.