engineering physics MCQ #4591

The time period of a simple pendulum is given by

engineering physics MCQ #4591

  1. Question 1

    Q1. The time period of a simple pendulum is given by

    • A) 2π √(l/g)
    • B) 2π √(g/l)
    • C) 2π √(l/g) ³
    • D) 1 / (2π √(l/g))

    Answer: 2π √(l/g)

    Explanation: Derived from SHM equation, time period T = 2π √(l/g), where l is pendulum length and g is acceleration due to gravity.