engineering physics MCQ #4596

The time period of a physical pendulum is given by

engineering physics MCQ #4596

  1. Question 1

    Q1. The time period of a physical pendulum is given by

    • A) 2π √(I/mgd)
    • B) 2π √(m/Igd)
    • C) 2π √(I/mg)
    • D) 2π √(mg/I)

    Answer: 2π √(I/mgd)

    Explanation: Time period T = 2π √(I/mgd), where I is moment of inertia, m is mass, g is acceleration due to gravity, and d is distance from pivot to center of mass.