engineering physics MCQ #4610

A particle executes SHM with amplitude A. Its maximum velocity is V. What is its velocity at x = A/2?

engineering physics MCQ #4610

  1. Question 1

    Q1. A particle executes SHM with amplitude A. Its maximum velocity is V. What is its velocity at x = A/2?

    • A) V √3/2
    • B) V/2
    • C) V √(3/4)
    • D) V/√2

    Answer: V √3/2

    Explanation: v = ω √(A² - x²). At x = A/2, v = ω √(A² - A²/4) = ω √(3A²/4) = V √3/2.