A particle executes SHM with amplitude A. What is the ratio of its kinetic energy to potential energy at x = A/2?
Q1. A particle executes SHM with amplitude A. What is the ratio of its kinetic energy to potential energy at x = A/2?
Answer: 3:1
Explanation: KE/PE = (A² - x²)/x² = (A² - A²/4)/(A²/4) = 3:1.