The wavelength of a spectral line is given by 1 / λ = R (1 / n1² - 1 / n2²). For the first line of Lyman series, n1 = 1 and n2 = 2.
Q1. The wavelength of a spectral line is given by 1 / λ = R (1 / n1² - 1 / n2²). For the first line of Lyman series, n1 = 1 and n2 = 2.
Answer: 1216 Å
Explanation: Substitute n1 = 1, n2 = 2, and R = 1.097 × 10⁷ m⁻¹ to get 1 / λ = 1.097 × 10⁷ (1 - 1/4) = 0.82275 × 10⁷, λ = 1216 Å.