The energy of the photon absorbed when an electron jumps from n = 1 to n = 3 is given by ΔE = E3 - E1.
Q1. The energy of the photon absorbed when an electron jumps from n = 1 to n = 3 is given by ΔE = E3 - E1.
Answer: 12.09 eV
Explanation: Calculate E3 and E1 using En = -13.6 / n² eV, then find ΔE = E3 - E1 = -1.51 - (-13.6) = 12.09 eV.