engineering physics MCQ #499

The energy of the photon emitted when an electron jumps from n = 3 to n = 2 in a hydrogen atom is

engineering physics MCQ #499

  1. Question 1

    Q1. The energy of the photon emitted when an electron jumps from n = 3 to n = 2 in a hydrogen atom is

    • A) 1.89 eV
    • B) 1.51 eV
    • C) 0.66 eV
    • D) 3.4 eV

    Answer: 1.89 eV

    Explanation: Calculate the energy difference between n = 3 and n = 2 using En = -13.6 / n² eV.