The energy of the electron in the ground state of hydrogen atom is -13.6 eV. What is its energy in the first excited state?
Q1. The energy of the electron in the ground state of hydrogen atom is -13.6 eV. What is its energy in the first excited state?
Answer: -3.4 eV
Explanation: Substitute n = 2 in En = -13.6 / n² eV to get E2 = -13.6 / 4 = -3.4 eV.