The frequency of a spectral line is given by f = (E2 - E1) / h. What is the frequency of the photon emitted when an electron jumps from n = 2 to n = 1?
Q1. The frequency of a spectral line is given by f = (E2 - E1) / h. What is the frequency of the photon emitted when an electron jumps from n = 2 to n = 1?
Answer: 2.46 * 10^15 Hz
Explanation: Calculate E2 and E1, then use f = (E2 - E1) / h, where h = 6.626 * 10^-34 Js.