What is the energy of a photon emitted when an electron jumps from n = 3 to n = 2 in a hydrogen atom?
Q1. What is the energy of a photon emitted when an electron jumps from n = 3 to n = 2 in a hydrogen atom?
Answer: 1.89 eV
Explanation: Energy of photon = 13.6 (1/2² - 1/3²) = 13.6 (1/4 - 1/9) = 1.89 eV, using Bohr's model energy level formula.