The frequency of the emitted radiation when an electron jumps from n = 4 to n = 2 is given by ΔE = h * ν. What is ν?
Q1. The frequency of the emitted radiation when an electron jumps from n = 4 to n = 2 is given by ΔE = h * ν. What is ν?
Answer: 6.17 x 10¹⁴ Hz
Explanation: First, calculate ΔE = E4 - E2 = (-0.85) - (-3.4) = 2.55 eV = 2.55 * 1.6 x 10⁻¹⁹ J. Then, ν = ΔE / h = 6.17 x 10¹⁴ Hz.