engineering physics MCQ #524

The shortest wavelength in the Balmer series corresponds to the transition from n = ∞ to n = 2. What is the wavelength?

engineering physics MCQ #524

  1. Question 1

    Q1. The shortest wavelength in the Balmer series corresponds to the transition from n = ∞ to n = 2. What is the wavelength?

    • A) 364 nm
    • B) 410 nm
    • C) 434 nm
    • D) 486 nm

    Answer: 364 nm

    Explanation: Using the Rydberg formula, 1 / λ = R * (1 / 2² - 0) = R / 4, λ = 4 / R = 364 nm.