engineering physics MCQ #530

The energy of the photon emitted when an electron jumps from n = 4 to n = 3 is given by ΔE = E₄ - E₃. What is ΔE?

engineering physics MCQ #530

  1. Question 1

    Q1. The energy of the photon emitted when an electron jumps from n = 4 to n = 3 is given by ΔE = E₄ - E₃. What is ΔE?

    • A) 0.66 eV
    • B) 0.85 eV
    • C) 1.51 eV
    • D) 0.31 eV

    Answer: 0.66 eV

    Explanation: E₄ = -0.85 eV and E₃ = -1.51 eV. ΔE = E₄ - E₃ = -0.85 - (-1.51) = 0.66 eV.