engineering physics MCQ #535

The wavelength of the second line of Balmer series is given by

engineering physics MCQ #535

  1. Question 1

    Q1. The wavelength of the second line of Balmer series is given by

    • A) 1 / λ = R * (1 / 2² - 1 / 4²)
    • B) 1 / λ = R * (1 / 3² - 1 / 5²)
    • C) 1 / λ = R * (1 / 2² - 1 / 3²)
    • D) 1 / λ = R * (1 / 4² - 1 / 6²)

    Answer: 1 / λ = R * (1 / 2² - 1 / 4²)

    Explanation: For the second line of Balmer series, n1 = 2 and n2 = 4, so 1 / λ = R * (1 / 2² - 1 / 4²).