engineering physics MCQ #539

The ionization energy of hydrogen atom is 13.6 eV. What is the energy required to remove an electron from n = 2?

engineering physics MCQ #539

  1. Question 1

    Q1. The ionization energy of hydrogen atom is 13.6 eV. What is the energy required to remove an electron from n = 2?

    • A) 3.4 eV
    • B) 6.8 eV
    • C) 13.6 eV
    • D) 10.2 eV

    Answer: 3.4 eV

    Explanation: Energy required = E∞ - E2 = 0 - (-13.6 / 4) = 3.4 eV, using En = -13.6 / n² eV.