The energy of the nth orbit of He+ is given by En = -54.4 / n² eV. What is the energy of the ground state?
Q1. The energy of the nth orbit of He+ is given by En = -54.4 / n² eV. What is the energy of the ground state?
Answer: -54.4 eV
Explanation: Substitute n = 1 in En = -54.4 / n² eV to get E1 = -54.4 eV.