The energy of the photon emitted when an electron jumps from n = 5 to n = 2 is
Q1. The energy of the photon emitted when an electron jumps from n = 5 to n = 2 is
Answer: 2.86 eV
Explanation: ΔE = E5 - E2 = (-0.544) - (-3.4) = 2.856 eV, using En = -13.6 / n² eV.