engineering physics MCQ #553

The energy of the nth orbit of Li++ is given by En = -122.4 / n² eV. What is the energy of the ground state?

engineering physics MCQ #553

  1. Question 1

    Q1. The energy of the nth orbit of Li++ is given by En = -122.4 / n² eV. What is the energy of the ground state?

    • A) -122.4 eV
    • B) -61.2 eV
    • C) -30.6 eV
    • D) -13.6 eV

    Answer: -122.4 eV

    Explanation: Substitute n = 1 in En = -122.4 / n² eV to get E1 = -122.4 eV.