The energy of the photon emitted when an electron jumps from n = 3 to n = 2 in hydrogen atom is
Q1. The energy of the photon emitted when an electron jumps from n = 3 to n = 2 in hydrogen atom is
Answer: 1.89 eV
Explanation: Using the energy level formula, E_n = -13.6 / n², we find the energy difference between n = 3 and n = 2 to be 1.89 eV.