The ionization energy of a hydrogen atom is 13.6 eV. What is the energy required to excite an electron from the ground state to the first excited state?
Q1. The ionization energy of a hydrogen atom is 13.6 eV. What is the energy required to excite an electron from the ground state to the first excited state?
Answer: 10.2 eV
Explanation: Calculate the energy difference between n = 1 and n = 2 using En = -13.6 / n² eV: ΔE = E2 - E1 = -3.4 - (-13.6) = 10.2 eV.