engineering physics MCQ #582

The ionization energy of a hydrogen-like ion with Z = 2 is 54.4 eV. What is the energy of the ground state?

engineering physics MCQ #582

  1. Question 1

    Q1. The ionization energy of a hydrogen-like ion with Z = 2 is 54.4 eV. What is the energy of the ground state?

    • A) -54.4 eV
    • B) -27.2 eV
    • C) -13.6 eV
    • D) -108.8 eV

    Answer: -54.4 eV

    Explanation: For a hydrogen-like ion, En = -13.6 * Z² / n² eV. For Z = 2 and n = 1, E1 = -54.4 eV.