engineering physics MCQ #602

The wavelength of a photon emitted when an electron jumps from n = 4 to n = 2 is given by 1 / λ = R * (1 / 2² - 1 / 4²). What is λ?

engineering physics MCQ #602

  1. Question 1

    Q1. The wavelength of a photon emitted when an electron jumps from n = 4 to n = 2 is given by 1 / λ = R * (1 / 2² - 1 / 4²). What is λ?

    • A) 486 nm
    • B) 434 nm
    • C) 410 nm
    • D) 656 nm

    Answer: 486 nm

    Explanation: 1 / λ = R * (1 / 4 - 1 / 16) = R * (3 / 16), λ = 16 / (3 * R) = 486 nm.