engineering physics MCQ #6097

A force of 5 N acts on a body, displacing it by 3 m. What is the work done?

engineering physics MCQ #6097

  1. Question 1

    Q1. A force of 5 N acts on a body, displacing it by 3 m. What is the work done?

    • A) 10 J
    • B) 15 J
    • C) 20 J
    • D) 25 J

    Answer: 15 J

    Explanation: Work done = F * d = 5 * 3 = 15 J, using the formula for work done.