A force F = 2x + 3 acts on a body, where x is in meters. What is the work done in displacing the body from x = 0 to x = 4 m?
Q1. A force F = 2x + 3 acts on a body, where x is in meters. What is the work done in displacing the body from x = 0 to x = 4 m?
Answer: 28 J
Explanation: Work equals the area under the force-distance graph. Integrate 2x + 3 from 0 to 4: the antiderivative is x squared plus 3x. At 4 this is 16 + 12 = 28 J. At 0 it is 0, so work done is 28 J.