engineering physics MCQ #6125

A force of 20 N acts on a body, displacing it by 3 m. What is the work done?

engineering physics MCQ #6125

  1. Question 1

    Q1. A force of 20 N acts on a body, displacing it by 3 m. What is the work done?

    • A) 50 J
    • B) 60 J
    • C) 65 J
    • D) 70 J

    Answer: 60 J

    Explanation: Work done = F * d = 20 * 3 = 60 J, using the formula for work done.