A spring of spring constant 200 N/m is compressed by 0.2 m. What is the energy stored?
Q1. A spring of spring constant 200 N/m is compressed by 0.2 m. What is the energy stored?
Answer: 4 J
Explanation: Energy stored = 1/2 kx² = 1/2 * 200 * 0.2² = 4 J, using the formula for energy stored in a spring.