A spring is stretched by 0.1 m. If its spring constant is 100 N/m, what is the energy stored?
Q1. A spring is stretched by 0.1 m. If its spring constant is 100 N/m, what is the energy stored?
Answer: 0.5 J
Explanation: Energy stored = 1/2 kx² = 1/2 * 100 * 0.1² = 0.5 J, using the formula for energy stored in a spring.