engineering physics MCQ #6135

A force of 10 N acts on a body, displacing it by 5 m. What is the work done?

engineering physics MCQ #6135

  1. Question 1

    Q1. A force of 10 N acts on a body, displacing it by 5 m. What is the work done?

    • A) 50 J
    • B) 20 J
    • C) 10 J
    • D) 0 J

    Answer: 50 J

    Explanation: Work done = F * d = 10 * 5 = 50 J, using the formula for work done.