engineering physics MCQ #6137

A body of mass 2 kg is moving with a velocity of 4 m/s. If its velocity is doubled, what is the change in kinetic energy?

engineering physics MCQ #6137

  1. Question 1

    Q1. A body of mass 2 kg is moving with a velocity of 4 m/s. If its velocity is doubled, what is the change in kinetic energy?

    • A) 24 J
    • B) 32 J
    • C) 48 J
    • D) 16 J

    Answer: 48 J

    Explanation: Initial KE = 1/2 * 2 * 4² = 16 J, final KE = 1/2 * 2 * 8² = 64 J, change = 64 - 16 = 48 J.