engineering physics MCQ #6142

A force of 5 N acts on a body, displacing it by 2 m at an angle of 60°. What is the work done?

engineering physics MCQ #6142

  1. Question 1

    Q1. A force of 5 N acts on a body, displacing it by 2 m at an angle of 60°. What is the work done?

    • A) 5 J
    • B) 10 J
    • C) 8 J
    • D) 3 J

    Answer: 5 J

    Explanation: Work done = F * d * cos(60°) = 5 * 2 * 0.5 = 5 J, using the formula for work done.