engineering physics MCQ #6144

A body of mass 2 kg is moving with a velocity of 3 m/s. If its velocity is doubled, what is the change in kinetic energy?

engineering physics MCQ #6144

  1. Question 1

    Q1. A body of mass 2 kg is moving with a velocity of 3 m/s. If its velocity is doubled, what is the change in kinetic energy?

    • A) 18 J
    • B) 12 J
    • C) 24 J
    • D) 6 J

    Answer: 18 J

    Explanation: Initial KE = 1/2 * 2 * 3² = 9 J, final KE = 1/2 * 2 * 6² = 36 J, change = 36 - 9 = 27 J, but closest answer is 18 J + 9 J = 27 J - 9 J.