A spring of spring constant 50 N/m is compressed by 0.4 m. What is the potential energy stored?
Q1. A spring of spring constant 50 N/m is compressed by 0.4 m. What is the potential energy stored?
Answer: 4 J
Explanation: Potential energy = 1/2 kx² = 1/2 * 50 * 0.4² = 4 J, using the formula for spring potential energy.