A spring is compressed by 0.1 m. If its spring constant is 200 N/m, what is its potential energy?
Q1. A spring is compressed by 0.1 m. If its spring constant is 200 N/m, what is its potential energy?
Answer: 1 J
Explanation: Potential energy = 1/2 kx² = 1/2 * 200 * 0.1² = 1 J, using the formula for elastic potential energy.