A particle is moving in a circular path with a radius of 3 m and a constant speed of 6 m/s. What is its period?
Q1. A particle is moving in a circular path with a radius of 3 m and a constant speed of 6 m/s. What is its period?
Answer: 3π s
Explanation: Period is given by T = 2πr / v = 2π(3) / 6 = π s, but v = rω = r(2π / T), so T = 2πr / v = 2π(3) / 6 = π s.