What is the ratio of the kinetic energies of two particles moving in circular paths with radii r and 2r, if their time periods are the same?
Q1. What is the ratio of the kinetic energies of two particles moving in circular paths with radii r and 2r, if their time periods are the same?
Answer: 1 : 4
Explanation: T = 2πr / v, so v ∝ r. KE = 0.5mv² ∝ r². Thus, KE ratio is (r / 2r)² = 1 / 4.