A cyclist is moving on a circular track. If the radius of the track is 40 m and the coefficient of friction is 0.2, what is the maximum speed?
Q1. A cyclist is moving on a circular track. If the radius of the track is 40 m and the coefficient of friction is 0.2, what is the maximum speed?
Answer: √(80) m/s
Explanation: Maximum speed is given by √(μrg) = √(0.2 * 40 * 10) = √80 m/s.