A stone is tied to a string and rotated in a horizontal circle of radius 1.5 m with a speed of 3 m/s. What is its centripetal force if the mass is 0.2 kg?
Q1. A stone is tied to a string and rotated in a horizontal circle of radius 1.5 m with a speed of 3 m/s. What is its centripetal force if the mass is 0.2 kg?
Answer: 1.2 N
Explanation: Centripetal force (F) = mv² / r = 0.2 * (3)² / 1.5 = 1.2 N, using the formula F = mv² / r.