engineering physics MCQ #715

A 5 kg object is moving in a circular path with a radius of 2 m at a speed of 4 m/s. What is the centripetal force?

engineering physics MCQ #715

  1. Question 1

    Q1. A 5 kg object is moving in a circular path with a radius of 2 m at a speed of 4 m/s. What is the centripetal force?

    • A) 20 N
    • B) 40 N
    • C) 60 N
    • D) 80 N

    Answer: 40 N

    Explanation: Centripetal force = (m * v²) / r = (5 * 4²) / 2 = 40 N, using the formula F = mv²/r.