engineering physics MCQ #72

The current in an AC circuit is given by I = 5 sin(100πt - π / 2). The time taken by the current to reach its peak value is

engineering physics MCQ #72

  1. Question 1

    Q1. The current in an AC circuit is given by I = 5 sin(100πt - π / 2). The time taken by the current to reach its peak value is

    • A) 1 / 50 s
    • B) 1 / 100 s
    • C) 1 / 25 s
    • D) 1 / 200 s

    Answer: 1 / 200 s

    Explanation: ω = 100π, so f = 50 Hz. Time to reach peak is T / 4 = 1 / (4 * 50) = 1 / 200 s.