engineering physics MCQ #721

A particle is moving in a circular path. If the radius is doubled and the speed is halved, what is the new centripetal force?

engineering physics MCQ #721

  1. Question 1

    Q1. A particle is moving in a circular path. If the radius is doubled and the speed is halved, what is the new centripetal force?

    • A) 1 / 8 of the original
    • B) 1 / 4 of the original
    • C) 1 / 2 of the original
    • D) same as the original

    Answer: 1 / 8 of the original

    Explanation: New F = m * (v/2)² / (2r) = (1/8) * mv²/r, using F = mv²/r.