engineering physics MCQ #724

A 2 kg object is moving in a circular path with a radius of 3 m. If the centripetal force is 24 N, what is its speed?

engineering physics MCQ #724

  1. Question 1

    Q1. A 2 kg object is moving in a circular path with a radius of 3 m. If the centripetal force is 24 N, what is its speed?

    • A) 4 m/s
    • B) 6 m/s
    • C) 8 m/s
    • D) 10 m/s

    Answer: 6 m/s

    Explanation: v² = F * r / m = 24 * 3 / 2 = 36, v = √36 = 6 m/s, using F = mv²/r.