A particle is moving in a circular path with a constant speed. If its radius is halved, what happens to its centripetal acceleration?
Q1. A particle is moving in a circular path with a constant speed. If its radius is halved, what happens to its centripetal acceleration?
Answer: It is quadrupled
Explanation: Centripetal acceleration (a_c) is given by v²/r. If r is halved, a_c becomes v²/(r/2) = 2v²/r, so it is doubled, no, it becomes 2 * v² / r, so the correct is it is doubled, no, the correct is 2 * (v² / (r/2)) is 2v²/(r/2) = 4 * (v² / r) = 4 * a_c.