A particle is moving in a circular path with a constant angular velocity. If its period is 2π s, what is its angular velocity?
Q1. A particle is moving in a circular path with a constant angular velocity. If its period is 2π s, what is its angular velocity?
Answer: 1 rad/s
Explanation: Angular velocity (ω) is given by 2π/T, where T is period. So, ω = 2π/(2π) = 1 rad/s.