A stone is tied to a string of length 0.5 m and is whirled in a horizontal circle at a rate of 2 revolutions per second. What is its centripetal acceleration?
Q1. A stone is tied to a string of length 0.5 m and is whirled in a horizontal circle at a rate of 2 revolutions per second. What is its centripetal acceleration?
Answer: 8π² m/s²
Explanation: First, find angular velocity (ω) = 2πf = 2π * 2 = 4π rad/s. Then, a_c = ω²r = (4π)² * 0.5 = 8π² m/s².