A particle is moving in a circular path with a radius of 2 m and a constant angular acceleration of 2 rad/s². If its initial angular velocity is 1 rad/s, what is its angular displacement after 3 seconds?
Q1. A particle is moving in a circular path with a radius of 2 m and a constant angular acceleration of 2 rad/s². If its initial angular velocity is 1 rad/s, what is its angular displacement after 3 seconds?
Answer: 12 rad
Explanation: Angular displacement (θ) is given by θ = ω0t + 1/2 αt², where ω0 is initial angular velocity and α is angular acceleration. So, θ = 1*3 + 1/2 * 2 * (3)² = 3 + 9 = 12 rad.