engineering physics MCQ #822

A particle is moving in a circular path with a radius of 2 m. If its angular velocity is 4 rad/s, find its linear acceleration.

engineering physics MCQ #822

  1. Question 1

    Q1. A particle is moving in a circular path with a radius of 2 m. If its angular velocity is 4 rad/s, find its linear acceleration.

    • A) 16 m/s²
    • B) 32 m/s²
    • C) 64 m/s²
    • D) 128 m/s²

    Answer: 32 m/s²

    Explanation: Linear acceleration (centripetal) = r * ω² = 2 * (4)² = 32 m/s², using a = r * ω² formula.